bad assignment error

Fixing "zsh: bad assignment" error in Linux

The other day I was trying to create an alias in Linux for repetitive commands. An alias is a name that is translated as another name or command (or a set of commands).

So, I tried to create the alias in the following manner:

And it threw me the following error:

If you are a regular user of the Linux command line, you must have identified the error on the previous command. But I was preoccupied with my program in C++ and I did not notice the obvious error here.

In fact, I thought it to be an error with the way I used the combination of error for the alias. So, I fiddled for a couple of minutes and just to make sure what I was doing wrong, tried this command:

Now, I was certain that there was no error with the commands this time but I git the same result as above:

And that’s when I realized my mistake. You see, I have been working a lot with C++ and was following the standard of using spaces before and after the assignment operator (=). And that is what I used here as well. And shell does not like the wastage of “space”.

I removed the extra white spaces before and after the = and voilà! There it worked like a charm.

In fact, the same error can be encountered with the export command as well or any other variable assignments in the shell. There should not be spaces before and after equals sign.

This taught me a lesson to not waste white space while dealing with shell scripts and Linux commands. It’s not the same as writing programs in other languages.

I would add this tiny learning lesson to my list of things to know about the Linux terminal.

I hope you would not have to waste your time with this problem if you mind those spaces before and after the equals sign.

Abhishek Prakash

Created It's FOSS 11 years ago to share my Linux adventures. Have a Master's degree in Engineering and years of IT industry experience. Huge fan of Agatha Christie detective mysteries 🕵️‍♂️

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fix(emotty): fix bad assignment error #9714

Conversation.

dracorp commented Mar 8, 2021

Standards checklist:.

• The PR title is descriptive.
• The PR doesn't replicate another PR which is already open.
• I have read the contribution guide and followed all the instructions.
• The code follows the code style guide detailed in the wiki.
• The code is mine or it's from somewhere with an MIT-compatible license.
• The code is efficient, to the best of my ability, and does not waste computer resources.
• The code is stable and I have tested it myself, to the best of my abilities.

Removed redundant spaces to prevent:

Sorry, something went wrong.

Successfully merging this pull request may close these issues.

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Why does Zsh complain of my variable assignment as "command not found"?

When I try to write a Zsh script on macOS Big Sur, Version 11.5.1, I noticed that it keeps failing to recognize my variables as variables.

Instead, Zsh treats them as UNIX-like commands.

Screenshot of the problem on the Terminal Application - variable assignment problem for Zsh shell scripts

In the screenshot linked above, I did the following on the Terminal application.

• Showed the contents of the simple Zsh shell script.
• Used the "ls -l" UNIX-like command to indicate its file permissions, and show that it is an executable Zsh shell script.
• Executed the Zsh shell script, which shows that the Zsh script interpreter complains of how my variable name is a "command not found".

The source code for my Zsh shell script is provided as follows:

Can you please kindly let me know what am I missing, and what did I do wrong?

I just want to assign values to variables in my Zsh shell scripts.

Thank you so much, and have a great day! Ciao!

• macos-bigsur

The syntax to assign a value to a variable is foo=bar , not foo = bar . Whitespaces matter. The latter syntax is a command foo with arguments = and bar .

Few examples of how = is interpreted:

This is not specific to Zsh. The POSIX shell ( sh ) and POSIX-compliant shells behave this way. Zsh (while not being POSIX-compliant in general) also follows.

• My upvote can only be recorded but not cast, since my reputation score is low for the "Super User" site of Stack Exchange. That said, thank you so much! It makes a lot of sense now. –  Giovanni Commented Aug 12, 2021 at 19:17

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PRIO-063 Bad I/O asg error. How to fix?

• June 29, 2017 at 5:05 PM
• Thread is Resolved

We have a pair of (used - new to us) Fanuc R-2000iA/210F robots with R-J3iB controls (Handling Tool Version V6.40-1K). I am currently getting a PRIO-063 Bad I/O asg error: Rack 85 Slot 21 error on both robots. It doesn't seem to affect them in their tasks/programs, but it's annoying seeing it on the screen (and maybe it does affect them in some way). After some research I found that Rack 85 is the ControlNet rack. These robots do not have the ControlNet cards installed. The programs I've created do not call these addresses at all. Under this error ( http://alarmcodes.com/fanuc-robot-al…-rack-d-slot-d/ ), it says to delete or update the assignments, but to this time I haven't been able to figure out how or where.

When I go to the I/O ControlNet board detail, I get:

Board: 1 Status: NOBOARD Motherboard: Full-slot Operation mode: ADPTR Param Change Mode: NET ULK Input error state: ZERO Scanner Err sevrty: STOP Adapter Err sevrty: WARN

ControlNet Parameters: MAC-ID: 30 NUT (us): 100000 SMAX: 0 UMAX: 99 Slot (us): 254 Gbpre (10us): 92 Gbstrt (10us): 61 Gbcenter (10us): 45

In Device List (DEV-LST) there is also a device with the following settings:

Input Header Words: 0

Status: ON MAC ID: 0 Device Name: [ ] Comment: [ ] Vendor ID: 0 Device Type: 0 Prod Code: 0 Maj Rev: 0 Min Rev: 0 Digital Inputs: 0 Digital outputs: 0 Analog Inputs: 0 Analog Outputs: 0 O-T RPI (us): 0 T-O RPI (us): 0 Path: [ ]

When I checked the SUMMARY.DG file (which I found during my research), it shows RACK 85 SLOT 21 under the following I/O:

IO CONFIGURATION::

DIN[ 1] START CYCLE DIN[ 4] RECIPE 1 DIN[ 5] RECIPE 2 DIN[ 6] RECIPE 3 DIN[ 7] RECIPE 4 DIN[ 8] RECIPE ENABLED DIN 1 - 8 RACK: 1 SLOT: 1 PORT: 1 DIN 9 - 16 RACK: 1 SLOT: 1 PORT: 9 DIN 609 - 616 RACK: 85 SLOT: 21 PORT: 1 DIN 617 - 624 RACK: 85 SLOT: 21 PORT: 9 DIN 625 - 632 RACK: 85 SLOT: 21 PORT: 17 DIN 633 - 640 RACK: 85 SLOT: 21 PORT: 25 DIN 641 - 648 RACK: 85 SLOT: 21 PORT: 33 DIN 649 - 656 RACK: 85 SLOT: 21 PORT: 41 DIN 657 - 664 RACK: 85 SLOT: 21 PORT: 49 DIN 665 - 672 RACK: 85 SLOT: 21 PORT: 57 DIN 673 - 680 RACK: 85 SLOT: 21 PORT: 65 DIN 681 - 688 RACK: 85 SLOT: 21 PORT: 73 DIN 689 - 696 RACK: 85 SLOT: 21 PORT: 81 DIN 697 - 704 RACK: 85 SLOT: 21 PORT: 89 DIN 705 - 712 RACK: 85 SLOT: 21 PORT: 97 DIN 713 - 720 RACK: 85 SLOT: 21 PORT: 105 DIN 721 - 728 RACK: 85 SLOT: 21 PORT: 113 DIN 729 - 736 RACK: 85 SLOT: 21 PORT: 121 DOUT[ 1] IN AUTO DOUT[ 2] IN HOME POS. DOUT[ 3] CYCLE COMPLETE DOUT[ 4] ROBOT ESTOP DOUT 1 - 8 RACK: 1 SLOT: 2 PORT: 1 DOUT 569 - 576 RACK: 85 SLOT: 21 PORT: 1 DOUT 577 - 584 RACK: 85 SLOT: 21 PORT: 9 DOUT 585 - 592 RACK: 85 SLOT: 21 PORT: 17 DOUT 593 - 600 RACK: 85 SLOT: 21 PORT: 25 DOUT 601 - 608 RACK: 85 SLOT: 21 PORT: 33 DOUT 609 - 616 RACK: 85 SLOT: 21 PORT: 41 DOUT 617 - 624 RACK: 85 SLOT: 21 PORT: 49 DOUT 625 - 632 RACK: 85 SLOT: 21 PORT: 57 DOUT 633 - 640 RACK: 85 SLOT: 21 PORT: 65 DOUT 641 - 648 RACK: 85 SLOT: 21 PORT: 73 DOUT 649 - 656 RACK: 85 SLOT: 21 PORT: 81 DOUT 657 - 664 RACK: 85 SLOT: 21 PORT: 89 DOUT 665 - 672 RACK: 85 SLOT: 21 PORT: 97 DOUT 673 - 680 RACK: 85 SLOT: 21 PORT: 105 DOUT 681 - 688 RACK: 85 SLOT: 21 PORT: 113 DOUT 689 - 696 RACK: 85 SLOT: 21 PORT: 121

When I check the I/O Digital configuration, it shows:

# RANGE RACK SLOT START STAT. 1 DI[1-16] 1 1 1 ACTIV 2 DI[17-512] 0 0 0 UNASG

# RANGE RACK SLOT START STAT. 1 DI[1-8] 1 1 1 ACTIV 2 DI[9-512] 0 0 0 UNASG

(No range above 512).

So, how do I delete or update the assignments?

• June 29, 2017 at 7:12 PM

To delete an assignment just go to your I/O config screen, cursor onto the line of the assignment you want to delete, press the DELETE button(above F4 i believe), and then press YES. I just did this in Roboguide to confirm the steps, but this was an R30iB controller so the steps or buttons might be a little different in the older R-J3iB controller.

I also use the SUMMARY.DG file alot. If I get a call about an issue with a robot I usually look there first in a robot's backup to get a good overview of the robot; IO config, options installed, software version, etc.

• June 29, 2017 at 8:06 PM

Did you try to perform Cold Start of the controller ?

• June 29, 2017 at 8:18 PM

Also you can clear ALL I/O assignment by going to:

MENU -> I/O -> Link Device

and than form softkeybar menu choose option CLR_ASG, than confirm that you want to clear ALL assignment and after this is done restart the controller.

But be aware this will clear ALL I/O , that means you need to set them again after restarting the robot. In your case it's not so many just one assignment.

• June 30, 2017 at 1:50 PM

Quote from K-Sky To delete an assignment just go to your I/O config screen, cursor onto the line of the assignment you want to delete, press the DELETE button(above F4 i believe), and then press YES. I just did this in Roboguide to confirm the steps, but this was an R30iB controller so the steps or buttons might be a little different in the older R-J3iB controller. I also use the SUMMARY.DG file alot. If I get a call about an issue with a robot I usually look there first in a robot's backup to get a good overview of the robot; IO config, options installed, software version, etc.

The address range listed (in the SUMMARY.DG file) for Rack 85, Slot 21 is not listed in the IO config, so I can't delete it (I tried).

Quote from ownagebyh4x Did you try to perform Cold Start of the controller ?

Many times.

Quote from ownagebyh4x Also you can clear ALL I/O assignment by going to: MENU -> I/O -> Link Device and than form softkeybar menu choose option CLR_ASG, than confirm that you want to clear ALL assignment and after this is done restart the controller. But be aware this will clear ALL I/O , that means you need to set them again after restarting the robot. In your case it's not so many just one assignment.

I'll try this next week when the line is not running.

• June 30, 2017 at 3:54 PM

Remember that I/O changes require a robot restart.....

• June 30, 2017 at 4:40 PM

Quote from tony gast Remember that I/O changes require a robot restart.....

Is that a Cold Start on the controller or just cycling the power to it?

• June 30, 2017 at 4:49 PM

You can just cycle power

• July 3, 2017 at 8:24 AM

I would first try to set the number of digital IOs to 1024 (controlled start -> PROGRAM SETUP Menu) and then, after a cold start, try to delete the assignments. You can set the number if IOs back to 512 when you're done. Also, check analog signals for any non-zero configuration (Rack/Slot/StartPt).

• July 4, 2017 at 2:57 PM

Quote from bidzej I would first try to set the number of digital IOs to 1024 (controlled start -> PROGRAM SETUP Menu) and then, after a cold start, try to delete the assignments. You can set the number if IOs back to 512 when you're done. Also, check analog signals for any non-zero configuration (Rack/Slot/StartPt).

Thanks bidzej. Unfortunately, my controller didn't have a menu under the Controlled Start to allow a Setup as you mentioned. BUT, because of what you mentioned, I was able to find a Variable under System/Variables called $MAX_DIG_PRT that I could set to 1024 (was 512). I did a Cold Start, deleted the I/O configuration that was assigned to the non-existant ControlNet boards, changed the variable back to 512, cold start and voila! NO BAD I/O rack assignment alarms anymore. Did this to both my robots and now I'm happy.

Thanks bidzej and to everyone with their suggestions.

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zsh: inconsistent error handling in assignments

This is zsh -f :

Why is local messing up error handling?

• variable-substitution
• process-substitution

From the zsh manual regarding the typeset builtin (which local is a special case of):

Unlike parameter assignment statements, typeset 's exit status on an assignment that involves a command substitution does not reflect the exit status of the command substitution. Therefore, to test for an error in a command substitution, separate the declaration of the parameter from its initialization: # WRONG typeset var1=$(exit 1) || echo "Trouble with var1" # RIGHT typeset var1 && var1=$(exit 1) || echo "Trouble with var1"

In your case:

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SC2276 – ShellCheck Wiki

This is interpreted as a command name containing = . bad assignment or comparison, problematic code:, correct code:.

ShellCheck found a command name containing an unquoted equals sign = . This was likely intended as either a comparison or an assignment.

To compare two values, use e.g. [ "$var" = "42" ]

To assign a value, use e.g. var="42"

Exceptions:

None, though you can quote the = to make ShellCheck ignore it: "$var=42" .

Related resources:

• Help by adding links to BashFAQ, StackOverflow, man pages, POSIX, etc!

ShellCheck is a static analysis tool for shell scripts. This page is part of its documentation.

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: bad expression: Invalid left-hand side in assignment

[[Open door|Sorter1][$CurrentPos.LocEntry[3] = 5; $CurrentPos.LocWall[3] = 5; $Reset = true; $DoorOpened = true]]

Originally I did try that normal link code method and what i was trying to achieve wasn't working so i wrongly assumed that you couldn't have [] within the link|passage code because it uses them, i was assuming it wasn't passing the values.

// WRONG: The closing square bracket of the array touches the closing pair of the markup, making them ambiguous. [[Go where?|There][$list to ["A", "B"]]] // CORRECT: The closing square bracket of the array is separated from the closing pair of the markup by a space. [[Go where?|There][$list to ["A", "B"] ]]

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SyntaxError: invalid assignment left-hand side

The JavaScript exception "invalid assignment left-hand side" occurs when there was an unexpected assignment somewhere. It may be triggered when a single = sign was used instead of == or === .

SyntaxError or ReferenceError , depending on the syntax.

What went wrong?

There was an unexpected assignment somewhere. This might be due to a mismatch of an assignment operator and an equality operator , for example. While a single = sign assigns a value to a variable, the == or === operators compare a value.

Typical invalid assignments

In the if statement, you want to use an equality operator ( === ), and for the string concatenation, the plus ( + ) operator is needed.

Assignments producing ReferenceErrors

Invalid assignments don't always produce syntax errors. Sometimes the syntax is almost correct, but at runtime, the left hand side expression evaluates to a value instead of a reference , so the assignment is still invalid. Such errors occur later in execution, when the statement is actually executed.

Function calls, new calls, super() , and this are all values instead of references. If you want to use them on the left hand side, the assignment target needs to be a property of their produced values instead.

Note: In Firefox and Safari, the first example produces a ReferenceError in non-strict mode, and a SyntaxError in strict mode . Chrome throws a runtime ReferenceError for both strict and non-strict modes.

Using optional chaining as assignment target

Optional chaining is not a valid target of assignment.

Instead, you have to first guard the nullish case.

• Assignment operators
• Equality operators

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Why I get "Invalid left-hand side in assignment"?

There is code:

I get this error:

Why "&&" is wrong?

• ecmascript-6

• are you missing if before the first set of parentheses? –  Dan O Commented Dec 1, 2017 at 3:32
• 1 result[id] = list[id] should be result[id] === list[id] as it is a condition –  Aravind Commented Dec 1, 2017 at 3:33
• @Aravind that is not correct. –  Pointy Commented Dec 1, 2017 at 3:38
• @DanO "if" must not be important, because all logical operator in ( ), not { } –  Turar Abu Commented Dec 1, 2017 at 3:43
• @TurarAbu see my answer: the problem is that your assignment expression at the end of the && list is not in parentheses. –  Pointy Commented Dec 1, 2017 at 3:43

2 Answers 2

The problem is that the assignment operator, = , is a low-precedence operator, so it's being interpreted in a way you don't expect. If you put that last expression in parentheses, it works:

• The real problem is using logical operators for control flow. –  user8897421 Commented Dec 1, 2017 at 3:50
• 1 @rockstar well sure :) But it's not erroneous and lots of hard-core library code does stuff like that, so people will see it in "respectable" places. –  Pointy Commented Dec 1, 2017 at 3:55

There seems to be a typo in your code:

result[id] = list[id] should be result[id] == list[id] or result[id] === list[id] (if you're doing a strict comparison)

• No. The code posted is using JavaScript logical short-circuiting operators to conditionally perform an operation. The change you suggest would make the code do nothing at all. –  Pointy Commented Dec 1, 2017 at 3:37
• The trouble at 4'th line. –  Turar Abu Commented Dec 1, 2017 at 3:40
• There's no way = is a short hand for == or === . They have different meanings altogether. I checked in my console and it worked fine when I changed it to result[id] == list[id] –  m-ketan Commented Dec 1, 2017 at 3:41
• @m-ketan he wants to use the assignment operator ( = ). If the statement does not perform an assignment, the code is useless. –  Pointy Commented Dec 1, 2017 at 3:42
• @Pointy Oh I see it now. –  m-ketan Commented Dec 1, 2017 at 3:44

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