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Mathematics LibreTexts

Section 12: Solving Ratio and Rate Problems

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Ratio Problem Solving

Here we will learn about ratio problem solving, including how to set up and solve problems. We will also look at real life ratio problems.

There are also ratio problem solving worksheets based on Edexcel, AQA and OCR exam questions, along with further guidance on where to go next if you’re still stuck.

What is ratio problem solving?

Ratio problem solving is a collection of word problems that link together aspects of ratio and proportion into more real life questions. This requires you to be able to take key information from a question and use your knowledge of ratios (and other areas of the curriculum) to solve the problem.

A ratio is a relationship between two or more quantities . They are usually written in the form a:b where a and b are two quantities. When problem solving with a ratio, the key facts that you need to know are,

  • What is the ratio involved?
  • What order are the quantities in the ratio?
  • What is the total amount / what is the part of the total amount known?
  • What are you trying to calculate ?

As with all problem solving, there is not one unique method to solve a problem. However, this does not mean that there aren’t similarities between different problems that we can use to help us find an answer. 

The key to any problem solving is being able to draw from prior knowledge and use the correct piece of information to allow you to get to the next step and then the solution.

Let’s look at a couple of methods we can use when given certain pieces of information.

What is ratio problem solving?

When solving ratio problems it is very important that you are able to use ratios. This includes being able to use ratio notation. 

For example, Charlie and David share some sweets in the ratio of 3:5. This means that for every 3 sweets Charlie gets, David receives 5 sweets.

Charlie and David share 40 sweets, how many sweets do they each get?

We use the ratio to divide 40 sweets into 8 equal parts. 

Then we multiply each part of the ratio by 5.

3 x 5:5 x 5 = 15:25

This means that Charlie will get 15 sweets and David will get 25 sweets.

  • Dividing ratios

Step-by-step guide: Dividing ratios (coming soon)

Ratios and fractions (proportion problems)

We also need to consider problems involving fractions. These are usually proportion questions where we are stating the proportion of the total amount as a fraction.

Simplifying and equivalent ratios

  • Simplifying ratios

Equivalent ratios

Units and conversions ratio questions

Units and conversions are usually equivalent ratio problems (see above).

  • If £1:\$1.37 and we wanted to convert £10 into dollars, we would multiply both sides of the ratio by 10 to get £10 is equivalent to \$13.70.
  • The scale on a map is 1:25,000. I measure 12cm on the map. How far is this in real life, in kilometres? After multiplying both parts of the ratio by 12 you must then convert 12 \times 25000=300000 \ cm to km by dividing the solution by 100 \ 000 to get 3km.

Notice that for all three of these examples, the units are important. For example if we write the mapping example as the ratio 4cm:1km, this means that 4cm on the map is 1km in real life.

Top tip: if you are converting units, always write the units in your ratio.

Usually with ratio problem solving questions, the problems are quite wordy . They can involve missing values , calculating ratios , graphs , equivalent fractions , negative numbers , decimals and percentages .

Highlight the important pieces of information from the question, know what you are trying to find or calculate , and use the steps above to help you start practising how to solve problems involving ratios.

How to do ratio problem solving

In order to solve problems including ratios:

Identify key information within the question.

Know what you are trying to calculate.

Use prior knowledge to structure a solution.

Explain how to do ratio problem solving

Explain how to do ratio problem solving

Ratio problem solving worksheet

Get your free ratio problem solving worksheet of 20+ questions and answers. Includes reasoning and applied questions.

Related lessons on ratio

Ratio problem solving is part of our series of lessons to support revision on ratio . You may find it helpful to start with the main ratio lesson for a summary of what to expect, or use the step by step guides below for further detail on individual topics. Other lessons in this series include:

  • How to work out ratio  
  • Ratio to fraction
  • Ratio scale
  • Ratio to percentage

Ratio problem solving examples

Example 1: part:part ratio.

Within a school, the number of students who have school dinners to packed lunches is 5:7. If 465 students have a school dinner, how many students have a packed lunch?

Within a school, the number of students who have school dinners to packed lunches is \bf{5:7.} If \bf{465} students have a school dinner , how many students have a packed lunch ?

Here we can see that the ratio is 5:7 where the first part of the ratio represents school dinners (S) and the second part of the ratio represents packed lunches (P).

We could write this as

Ratio problem solving example 1 step 1

Where the letter above each part of the ratio links to the question.

We know that 465 students have school dinner.

2 Know what you are trying to calculate.

From the question, we need to calculate the number of students that have a packed lunch, so we can now write a ratio below the ratio 5:7 that shows that we have 465 students who have school dinners, and p students who have a packed lunch.

Ratio problem solving example 1 step 2

We need to find the value of p.

3 Use prior knowledge to structure a solution.

We are looking for an equivalent ratio to 5:7. So we need to calculate the multiplier. We do this by dividing the known values on the same side of the ratio by each other.

So the value of p is equal to 7 \times 93=651.

There are 651 students that have a packed lunch.

Example 2: unit conversions

The table below shows the currency conversions on one day.

Ratio problem solving example 2

Use the table above to convert £520 (GBP) to Euros € (EUR).

Ratio problem solving example 2

Use the table above to convert \bf{£520} (GBP) to Euros \bf{€} (EUR).

The two values in the table that are important are GBP and EUR. Writing this as a ratio, we can state

Ratio problem solving example 2 step 1 image 2

We know that we have £520.

We need to convert GBP to EUR and so we are looking for an equivalent ratio with GBP = £520 and EUR = E.

Ratio problem solving example 2 step 2

To get from 1 to 520, we multiply by 520 and so to calculate the number of Euros for £520, we need to multiply 1.17 by 520.

1.17 \times 520=608.4

So £520 = €608.40.

Example 3: writing a ratio 1:n

Liquid plant food is sold in concentrated bottles. The instructions on the bottle state that the 500ml of concentrated plant food must be diluted into 2l of water. Express the ratio of plant food to water respectively in the ratio 1:n.

Liquid plant food is sold in concentrated bottles. The instructions on the bottle state that the \bf{500ml} of concentrated plant food must be diluted into \bf{2l} of water . Express the ratio of plant food to water respectively as a ratio in the form 1:n.

Using the information in the question, we can now state the ratio of plant food to water as 500ml:2l. As we can convert litres into millilitres, we could convert 2l into millilitres by multiplying it by 1000.

2l = 2000ml

So we can also express the ratio as 500:2000 which will help us in later steps.

We want to simplify the ratio 500:2000 into the form 1:n.

We need to find an equivalent ratio where the first part of the ratio is equal to 1. We can only do this by dividing both parts of the ratio by 500 (as 500 \div 500=1 ).

Ratio problem solving example 3 step 3

So the ratio of plant food to water in the form 1:n is 1:4.

Example 4: forming and solving an equation

Three siblings, Josh, Kieran and Luke, receive pocket money per week proportional to their age. Kieran is 3 years older than Josh. Luke is twice Josh’s age. If Josh receives £8 pocket money, how much money do the three siblings receive in total?

Three siblings, Josh, Kieran and Luke, receive pocket money per week proportional to their ages. Kieran is \bf{3} years older than Josh . Luke is twice Josh’s age. If Luke receives \bf{£8} pocket money, how much money do the three siblings receive in total ?

We can represent the ages of the three siblings as a ratio. Taking Josh as x years old, Kieran would therefore be x+3 years old, and Luke would be 2x years old. As a ratio, we have

Ratio problem solving example 4 step 1

We also know that Luke receives £8.

We want to calculate the total amount of pocket money for the three siblings.

We need to find the value of x first. As Luke receives £8, we can state the equation 2x=8 and so x=4.

Now we know the value of x, we can substitute this value into the other parts of the ratio to obtain how much money the siblings each receive.

Ratio problem solving example 4 step 3

The total amount of pocket money is therefore 4+7+8=£19.

Example 5: simplifying ratios

Below is a bar chart showing the results for the colours of counters in a bag.

Ratio problem solving example 5

Express this data as a ratio in its simplest form.

From the bar chart, we can read the frequencies to create the ratio.

Ratio problem solving example 5 step 1

We need to simplify this ratio.

To simplify a ratio, we need to find the highest common factor of all the parts of the ratio. By listing the factors of each number, you can quickly see that the highest common factor is 2.

\begin{aligned} &12 = 1, {\color{red} 2}, 3, 4, 6, 12 \\\\ &16 = 1, {\color{red} 2}, 4, 8, 16 \\\\ &10 = 1, {\color{red} 2}, 5, 10 \end{aligned}

HCF (12,16,10) = 2

Dividing all the parts of the ratio by 2 , we get

Ratio problem solving example 5 step 3

Our solution is 6:8:5 .

Example 6: combining two ratios

Glass is made from silica, lime and soda. The ratio of silica to lime is 15:2. The ratio of silica to soda is 5:1. State the ratio of silica:lime:soda.

Glass is made from silica, lime and soda. The ratio of silica to lime is \bf{15:2.} The ratio of silica to soda is \bf{5:1.} State the ratio of silica:lime:soda .

We know the two ratios

Ratio problem solving example 6 step 1

We are trying to find the ratio of all 3 components: silica, lime and soda.

Using equivalent ratios we can say that the ratio of silica:soda is equivalent to 15:3 by multiplying the ratio by 3.

Ratio problem solving example 6 step 3 image 1

We now have the same amount of silica in both ratios and so we can now combine them to get the ratio 15:2:3.

Ratio problem solving example 6 step 3 image 2

Example 7: using bar modelling

India and Beau share some popcorn in the ratio of 5:2. If India has 75g more popcorn than Beau, what was the original quantity?

India and Beau share some popcorn in the ratio of \bf{5:2.} If India has \bf{75g} more popcorn than Beau , what was the original quantity?

We know that the initial ratio is 5:2 and that India has three more parts than Beau.

We want to find the original quantity.

Drawing a bar model of this problem, we have

Ratio problem solving example 7 step 1

Where India has 5 equal shares, and Beau has 2 equal shares.

Each share is the same value and so if we can find out this value, we can then find the total quantity.

From the question, India’s share is 75g more than Beau’s share so we can write this on the bar model.

Ratio problem solving example 7 step 3 image 1

We can find the value of one share by working out 75 \div 3=25g.

Ratio problem solving example 7 step 3 image 2

We can fill in each share to be 25g.

Ratio problem solving example 7 step 3 image 3

Adding up each share, we get

India = 5 \times 25=125g

Beau = 2 \times 25=50g

The total amount of popcorn was 125+50=175g.

Common misconceptions

  • Mixing units

Make sure that all the units in the ratio are the same. For example, in example 6 , all the units in the ratio were in millilitres. We did not mix ml and l in the ratio.

  • Ratio written in the wrong order

For example the number of dogs to cats is given as the ratio 12:13 but the solution is written as 13:12.

  • Ratios and fractions confusion

Take care when writing ratios as fractions and vice-versa. Most ratios we come across are part:part. The ratio here of red:yellow is 1:2. So the fraction which is red is \frac{1}{3} (not \frac{1}{2} ).

Ratio problem solving common misconceptions

  • Counting the number of parts in the ratio, not the total number of shares

For example, the ratio 5:4 has 9 shares, and 2 parts. This is because the ratio contains 2 numbers but the sum of these parts (the number of shares) is 5+4=9. You need to find the value per share, so you need to use the 9 shares in your next line of working.

  • Ratios of the form \bf{1:n}

The assumption can be incorrectly made that n must be greater than 1 , but n can be any number, including a decimal.

Practice ratio problem solving questions

1. An online shop sells board games and computer games. The ratio of board games to the total number of games sold in one month is 3:8. What is the ratio of board games to computer games?

GCSE Quiz True

8-3=5 computer games sold for every 3 board games.

2. The volume of gas is directly proportional to the temperature (in degrees Kelvin). A balloon contains 2.75l of gas and has a temperature of 18^{\circ}K. What is the volume of gas if the temperature increases to 45^{\circ}K?

3. The ratio of prime numbers to non-prime numbers from 1-200 is 45:155. Express this as a ratio in the form 1:n.

4. The angles in a triangle are written as the ratio x:2x:3x. Calculate the size of each angle.

5. A clothing company has a sale on tops, dresses and shoes. \frac{1}{3} of sales were for tops, \frac{1}{5} of sales were for dresses, and the rest were for shoes. Write a ratio of tops to dresses to shoes sold in its simplest form.

6. During one month, the weather was recorded into 3 categories: sunshine, cloud and rain. The ratio of sunshine to cloud was 2:3 and the ratio of cloud to rain was 9:11. State the ratio that compares sunshine:cloud:rain for the month.

Ratio problem solving GCSE questions

1. One mole of water weighs 18 grams and contains 6.02 \times 10^{23} water molecules.

Write this in the form 1gram:n where n represents the number of water molecules in standard form.

2. A plank of wood is sawn into three pieces in the ratio 3:2:5. The first piece is 36cm shorter than the third piece.

Calculate the length of the plank of wood.

5-3=2 \ parts = 36cm so 1 \ part = 18cm

3. (a) Jenny is x years old. Sally is 4 years older than Jenny. Kim is twice Jenny’s age. Write their ages in a ratio J:S:K.

(b) Sally is 16 years younger than Kim. Calculate the sum of their ages.

Learning checklist

You have now learned how to:

  • Relate the language of ratios and the associated calculations to the arithmetic of fractions and to linear functions
  • Develop their mathematical knowledge, in part through solving problems and evaluating the outcomes, including multi-step problems
  • Make and use connections between different parts of mathematics to solve problems

The next lessons are

  • Compound measures
  • Best buy maths

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Rates and ratios

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  • Class ratio II
  • Class ratio III

The ratio is the relationship of two numbers. For example you have 2 flashlights and 5 batteries. To compare the ratio between the flashlights and the batteries we divide the set of flashlights with the set of batteries.

The ratio is 2 to 5 or 2:5 or 2/5. All these describe the ratio in different forms of fractions. The ratio can consequently be expressed as fractions or as a decimal. 2:5 in decimals is 0.4.

A rate is a little bit different than the ratio, it is a special ratio. It is a comparison of measurements that have different units, like cents and grams. A unit rate is a rate with a denominator of 1.

Sarah is buying jellybeans for her best friend's birthday party. She buys a bag of 10 lb of jellybeans that costs $45. Sarah is wondering how much 1 lb of jellybeans cost.

$$\$ 45=4500 \, cents$$

$$\frac{4500 \: cents}{10\: lb}=\frac{4500 \: cents{\color{green} {\, \div\, 10}}}{10\: lb{\color{green} {\, \div\, 10}}}=\frac{450 \: cents}{1\: lb}$$

$$1\: lb=450\: cents=\$ 4.50$$

Video lesson

Express the ratio as a fraction in simplest form and as a decimal

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Ratio, Proportion and Rates of Change - Short Problems

ratio and rate problem solving

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It is 225 minutes until midnight. What time is it on a 24-hour digital clock?

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Marcus' atrium was a square with each side 50 pedes long. How many times did Marcus have to walk round his atrium to complete his daily exercise of 8 stadia?

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How far away was the lightning if the flash and the thunderclap were 6 seconds apart?

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A Classy Ratio

There are six more girls than boys in Miss Spelling's class of 24 pupils. What is the ratio of girls to boys in the class?

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Can you work out how many brothers and sisters are in the family?

Dean's Mountain

Dean runs down the mountain at 12 km per hour. How long does it take him to run down the mountain?

Draining a Pool

The water is being drained from a pool. After how long will the depth of the pool be 144 cm?

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An athletics club has girl, boy and adult members. How many members does the club have?

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How many minutes are there between 11:41 and 14:02?

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If three brothers will get £20 more if they do not share their money with their sister, how much money is there?

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How Many Swimmers?

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Out of Sync

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Decimal Clock

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Off the Cuff

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Musical Maths

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The London Eye

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Crude Calculation

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How many barleycorns are there in one inch?

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Does Joseph have too many sheep in his flock...

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On which of the hare's laps will she first pass the tortoise?

Two trains started simultaneously, each travelling towards the other. How long did each train need to complete the journey?

Fraction of Percentages

What is $W$ as a fraction of $Z?$

Traffic Jam

Emily's journey home took 25% longer than usual. By what percentage was her average speed reduced?

Late for Work

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Backwards Laps

If two friends run in opposite directions around a track, and they pass each other every 24 seconds, how long do they take to complete a lap?

Chris cycled faster than expected. Can you work out his average speed?

What is the ratio of the lengths of the candles?

Petrol Stop

From the information given, can you work out how long Roberto drove for after putting petrol in his car?

Marathon Mission

Minnie trained more for the London Marathon this year, so her speed increased. By what percentage did her time decrease?

Walk up the Escalator

Can you work out how long Aimee would take to get up the escalator if she walked?

100m Sprint

Anna, Bridget and Carol run a race. Can you work out where Carol was when Anna finished?

Flower Show

How long will it take six gardeners to dig six circular flower beds?

Boys and Girls

Can you find the total number of students in the school, given some information about ratios?

Televisual Technology

If a new and an old television have screens of the same area, what is the ratio of their widths?

ratio and rate problem solving

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Table of Contents

Last modified on April 25th, 2024

#ezw_tco-2 .ez-toc-title{ font-size: 120%; ; ; } #ezw_tco-2 .ez-toc-widget-container ul.ez-toc-list li.active{ background-color: #ededed; } chapter outline

Ratios and rates.

Ratio and rates are frequently used together in everyday life to compare two quantities. While calculating the amount to be paid to shopkeepers to the changes, we will get back; all involve calculating rates of quantities in the form of a ratio.

They also calculate a population’s birth, mortality, or death rate. The incidence of COVID-19 over a region, district, or state and its death rate in a country are all calculated based on ratios and rates.

A ratio compares two quantities having the same units. It is written using a colon ‘:’, for example, 2:3, and is also written in fraction form as ${\dfrac{2}{3}}$.

For example, the expression between 20kg of sugar and 14 kg of wheat represents a ratio.

A rate is a unique ratio that compares 2 quantities with different units.

For example, if a man covers 3 km in 30 minutes, it is written as 3 km/30 minutes.

A unit rate is a rate with a denominator of 1.

Let us use the concept of ratios and rates to solve some problems.

Solved Examples

A frog limps 180 times in 10 seconds. Write the rate as a fraction in the lowest terms.

${\dfrac{180 \ times}{10 \ seconds}}$ = ${\dfrac{180}{10}=\dfrac{18}{1}}$ So, the rate is 18 limps per second.

A swimmer swims 30 laps in 60 minutes. Find the time it takes the swimmer to cover one lap.

${\dfrac{60 \ laps}{30 \ minutes}}$ = ${\dfrac{60}{30}=\dfrac{2}{1}}$ = 2 minutes Thus, the time taken by the swimmer to cover one lap is 2 minutes

If a truck travels 24 miles in 2 hours, calculate the average speed of the truck.

= ${\dfrac{24 \ miles}{2 \ hours}}$ = ${\dfrac{24}{2}=\dfrac{12}{1}}$ = 12 miles/hour Thus, the average speed of the truck is 12 miles/hour.

Ratio and rates are frequently used together in our everyday life for comparing two quantities. Calculating the amount to be paid to a shopkeeper and the amount of return we will get back involves finding rates of quantities in the form of ratios.

They are also used to calculate a population’s birth, mortality, or death rate.

A ratio is a comparison of two quantities having the same units. It is written using a colon ‘:’, for example, 2:3, and is also written in fraction form as ${\dfrac{2}{3}}$.

For example, the expression between 20kg of sugar and 14 kg of wheat is an example of a ratio.

A rate is a special kind of ratio that compares between 2 quantities having different units.

For example, if a man covers 3 km in 30 minutes, it is written as 3 km/30 minutes as an example of the rate.

If a car travels 24 miles in 2 hours, calculate the average speed of the car.

= ${\dfrac{24 \ miles}{2 \ hours}}$ = ${\dfrac{24}{2}=\dfrac{12}{1}}$ = 12 miles/hour Thus, the average speed of the car is 12 miles/hour

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How to Solve Rate Problems - Grade 7 Math Questions With Detailed Solutions

How to solve questions on rates in math? Grade 7 math questions are presented along with detailed Solutions and explanations included.

What are rates in math and where are they needed? The rate is a ratio of two quantities having different units. Where are they needed? Example 1: Car A travels 150 kilometers in 3 hours. Car B travels 220 kilometers in 4 hours. We assume that both car travels at constant speeds. Which of the two cars travels faster? Solution Car A travels 150 kilometers in 3 hours. In one hour it travels \( \dfrac{150 \,\, \text{kilometers}}{3 \,\, \text{hours}} = \dfrac{50 \,\, \text{km}}{1 \,\, \text{hour}} \) = 50 km / hour Car B travels 220 kilometers in 4 hours. In one hour it travels \( \dfrac{220 \,\, \text{kilometers}}{4 \,\, \text{hours}} = \dfrac{55 \,\, \text{km}}{1 \,\, \text{hour}} \) = 55 km / hour The quantities 50 km / hour and 55 km / hour are called unit rates because the denominator is one unit of time: 1 hour. In this case the unit rates can be used to find out which car travels faster because we now know how many kilometers are traveled by each car in one hour and we can therefore compare the speed (or rates) and say that car B travels faster.

Example 2: A car travels 150 kilometers in 3 hours. We assume that the car travels at a constant speed. How many hours are needed for this car to travel 250 kilometers at the same speed? Let t be the number of hours needed to travel 250 kilometers. Since the car travels at a constant rate (speed), we can write that the unit rate is the same whatever values for distance and time we use. Hence we write \( \dfrac{150 \,\, \text{km}}{3\,\,\text{hour}} = \dfrac{250 \,\, \text{km}}{\text{t}} \) , t in hours The above equation in t has the form. \( \dfrac{a}{b} = \dfrac{c}{d} \) Multiply both terms of the above by the product of the denominators \(b \times d\). \( b \times d \times \dfrac{a}{b} = b \times d \times \dfrac{c}{d} \) Simplify \( \cancel{b}\times d \times\dfrac{a}{\cancel{b}} = b \times \cancel{d} \times \dfrac{c}{\cancel{d}} \) to obtain \( a \times d = b \times c \) Hence the equations \( \dfrac{a}{b} = \dfrac{c}{d} \) and \( a \times d = b \times c \) are equivalent and have the same solution. This method of changing an equation from fractions on each side to products on each side is called "cross muliply" method which we will use to solve our problems. We now go back to our equation \( \dfrac{150 \,\, \text{km}}{3\,\,\text{hour}} = \dfrac{250 \,\, \text{km}}{\text{t}} \) and use the "cross multiply" method to write it as follows. \( 150 \,\, \text{km} \times t = 250 \text{km}\times 3 \text{hours} \) Since we need to find t, we then isolate it by dividing both sides of the above equation by \( 150 \,\, \text{km} \). \( \dfrac{150 \,\, \text{km} \times t}{150 \,\, \text{km}} = \dfrac{250 \text{km}\times 3 \text{hours}}{150 \,\, \text{km}} \) Simplify. \( \dfrac{\cancel{150 \,\, \text{km}} \times t}{\cancel{150 \,\, \text{km}}} = \dfrac{250 \cancel{\text{km}}\times 3 \text{hours}}{150 \,\, \cancel{\text{km}}} \) \( t = \dfrac{250 \times 3}{150} \, \, \text{hours} = 5 \,\, \text{hours}\)

The exercises below with solutions and explanations are all about solving rate problems.

Solve the following rate problems.

  • The distance between two cities on the map is 15 centimeters. The scales on the map is 5 centimeters to 15 kilometers. What is the real distance, in kilometers, between the two cities?
  • A car consumes 10 gallons of fuel to travel a distance of 220 miles. Assuming a constant rate of consumption, how many gallons are needed to travel 330 miles?
  • Ten tickets to a cinema theater costs $66. Wha is the cost of 22 tickets to the same cinema theater?
  • Cans of soda are packaged in boxes containing the same number of cans. There are 36 cans in 4 boxes. a) How many cans are there in 7 boxes? b) How many boxes are needed to package 99 cans of soda?
  • Joe bought 4 kilograms of apples at the cost of $15. How much would he pay for 11 kilograms of the same apples in the same shop?
  • It takes a pump 10 minutes to move 55 gallons of water up a hill. Using the same pump under the same condition; a) how much water is moved in 22 minutes? b) how long does it take to move 165 gallons of water?
  • A container with 324 liters of water, leaks 3 liters every 5 hours. How long does it take for the container to become empty?
  • Twenty one cans of tomato paste of the same size have a weight of 7300 grams. What is the weight of 5 cans?
  • An empty container is being filled with water at the rate of 5 liters every 45 seconds and leaks water at the rate of one liter every 180 seconds. What is the quantity of water in the container after one hour?

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Word Problems Involving Rates and Ratios

Word Problems Involving Rates and Ratios

The ratio is to compare two numbers. Rate is one type of ratio and is used to measure the variety of one thing or quantity in comparison to other. Word problems involving comparing rates deal with distances, time, rates, wind or water current, money, and age.

A step-by-step guide to solving rates and ratios word problems

To solve the word problems involving rates and ratios, follow these steps: Step 1: Find the known ratio and the unknown ratio. Step 2: Write the proportion. Step 3: Use cross-multiply and solve. Step 4: Plug the result into the unknown ratio to check the answers.

Word Problems Involving Rates and Ratios – Examples 1

If 11 apple pies cost $88, what will 8 apple pies cost? Solution: Write as a rate. \(\frac{88÷11}{11÷11}=\frac{8}{1}\) Write a proportion to know the cost of 8 apple pies. \(\frac{8}{1}=\frac{x}{6}→8×6=1×x→x=48\)

Word Problems Involving Rates and Ratios – Examples 2

If 6 cookbooks cost $120, how much would a dozen cookbooks cost? Solution: Write as a rate. \(\frac{120÷6}{6÷6}=\frac{20}{1}\) Write a proportion to know the cost of 12 cookbooks. \(\frac{20}{1}=\frac{x}{12}→20×12=1×x→x=240\)

by: Effortless Math Team about 1 year ago (category: Articles )

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Mastering Grade 6 Math Word Problems The Ultimate Guide to Tackling 6th Grade Math Word Problems

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Use the generator to make customized ratio worksheets. Experiment with the options to see what their effect is.

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Primary Grade Challenge Math by Edward Zaccaro

A good book on problem solving with very varied word problems and strategies on how to solve problems. Includes chapters on: Sequences, Problem-solving, Money, Percents, Algebraic Thinking, Negative Numbers, Logic, Ratios, Probability, Measurements, Fractions, Division. Each chapter’s questions are broken down into four levels: easy, somewhat challenging, challenging, and very challenging.

Can Economic Growth Help Solve Our Debt Problem?

The U.S. is among the most indebted countries in the world—and the problem is only getting worse.

The federal government’s debt is currently $33 trillion and annual deficits just reached the highest in U.S. history outside of the pandemic years (at nearly $2 trillion ). Not only are we spending more than we’re taking in, but the long-run growth in our spending is outpacing the growth in our revenue.

If the lessons from other countries dealing with similar problems are any indication, fixing this problem is going to require a combination of spending cuts and tax hikes. But there’s a third factor that could help alleviate some of the pain involved: economic growth .

Economic Growth, Deficits, and Debt

The faster the economy grows, the less pressure there is to raise taxes and cut spending.

With more businesses and workers, the tax base The tax base is the total amount of income, property, assets, consumption, transactions, or other economic activity subject to taxation by a tax authority. A narrow tax base is non-neutral and inefficient. A broad tax base reduces tax administration costs and allows more revenue to be raised at lower rates. expands, meaning the government can collect more tax revenue without raising rates.

To illustrate, suppose we have an economy with a GDP of $1 trillion and an average tax rate The average tax rate is the total tax paid divided by taxable income . While marginal tax rates show the amount of tax paid on the next dollar earned, average tax rates show the overall share of income paid in taxes. of 20 percent. Total tax revenue would be $200 billion. Let’s say the economy grows by 5 percent, bringing the new GDP to $1.05 trillion. With the tax rate unchanged at 20 percent, the new tax revenue would be $210 billion—a $10 billion increase without touching the tax rate.

A growing economy brings in more tax revenue, which reduces the relative debt burden. This gives lawmakers some breathing room to address fiscal imbalances (think gradual tweaks, not drastic measures).

What Is the Debt-to-GDP Ratio and Why Does It Matter?

The debt-to-GDP ratio is a measure of how much debt the federal government holds compared to how much it produces (i.e., the size of its economy) in a year. For example, say you borrowed $10,000 to start a business and you sold $50,000 worth of products. Your personal “debt-to-GDP” ratio would be 20 percent.

But what would happen if your debt-to-GDP ratio was 115 percent (like the U.S. in 2021)? You’d owe more than you produced in a year.

This ratio gives valuable insight into the sustainability of a country’s economy. If it gets too high, a country might struggle to pay back its debts, leading to a host of undesirable consequences. For example, interest costs to service the debt would become a bigger part of the budget, taking resources away from other priorities. And sometimes governments are tempted to print money to deal with the problem, which causes inflation Inflation is when the general price of goods and services increases across the economy, reducing the purchasing power of a currency and the value of certain assets. The same paycheck covers less goods, services, and bills. It is sometimes referred to as a “ hidden tax ,” as it leaves taxpayers less well-off due to higher costs and “bracket creep,” while increasing the government’s spending power. . While there’s disagreement about how high is too high, a debt-to-GDP ratio of 100 percent is a common milestone economists look out for.

How Taxes Affect Economic Growth

One way policymakers can promote economic growth is through tax policies that encourage people to work, save , and invest .

For example, allowing businesses to write off investments in the year they occur rather than over time (which decreases their value) makes investments more profitable. This, in turn, encourages more investments, which boosts productivity and can lead to more jobs and higher wages.

To be sure, some of these tax policies would decrease revenue, but the growing economy could help partially offset the reduction.

The Way Forward

With much of the 2017 tax reform law expiring in less than two years, Congress will get the chance to rewrite the tax code. And while a sustainable approach will require addressing the underlying drivers of the debt—i.e., mandatory spending programs like Social Security and Medicare—lawmakers should prioritize policies that lower the country’s debt-to-GDP ratio the most.

The bottom line: improving the country’s fiscal situation won’t be comfortable, but economic growth can help cushion the blow.

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Course: 6th grade   >   Unit 3

  • Intro to rates
  • Solving unit rate problem
  • Solving unit price problem

Rate problems

  • Comparing rates example
  • Comparing rates
  • Rate review

ratio and rate problem solving

  • Your answer should be
  • an integer, like 6 ‍  
  • an exact decimal, like 0.75 ‍  
  • a simplified proper fraction, like 3 / 5 ‍  
  • a simplified improper fraction, like 7 / 4 ‍  
  • a mixed number, like 1   3 / 4 ‍  

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COMMENTS

  1. Ratios and rates

    Practice. Ratios with tape diagrams Get 3 of 4 questions to level up! Equivalent ratios with equal groups Get 3 of 4 questions to level up! Create double number lines Get 3 of 4 questions to level up! Ratios with double number lines Get 3 of 4 questions to level up! Relate double number lines and ratio tables Get 3 of 4 questions to level up!

  2. Ratio Problem Solving

    Use ratio and rate reasoning to solve real-world and mathematical problems, for example, by reasoning about tables of equivalent ratios, tape diagrams, double number line diagrams, or equations. Grade 7 - Ratio and Proportional Relationships (7.RP.A.2)

  3. 4.1.1: Simplifying Ratios and Rates

    Write a ratio comparing the number of women to the total number of people at the party. 10÷2 22÷2 = 5 11 10 ÷ 2 22 ÷ 2 = 5 11. Simplify the ratio. 10 and 22 have a common factor of 2. 5⋅11 6⋅11 = 55 66 5⋅6 11⋅6 = 30 66 5 ⋅ 11 6 ⋅ 11 = 55 66 5 ⋅ 6 11 ⋅ 6 = 30 66. Rewrite each fraction with a common denominator, 66.

  4. Ratio

    Use ratio and rate reasoning to solve real-world and mathematical problems, for example, by reasoning about tables of equivalent ratios, tape diagrams, double number line diagrams, or equations. Grade 6 - Ratios and Proportions (6.RP.A.3b) Solve unit rate problems including those involving unit pricing and constant speed.

  5. Section 12: Solving Ratio and Rate Problems

    This page titled Section 12: Solving Ratio and Rate Problems is shared under a CC BY 4.0 license and was authored, remixed, and/or curated by Illustrative Mathematics via source content that was edited to the style and standards of the LibreTexts platform; a detailed edit history is available upon request. 11.4: Comparing Situations by ...

  6. Math Antics

    Learn More at mathantics.comVisit http://www.mathantics.com for more Free math videos and additional subscription based content!

  7. Ratio Problem Solving

    Ratio problem solving GCSE questions. 1. One mole of water weighs 18 18 grams and contains 6.02 \times 10^ {23} 6.02 × 1023 water molecules. Write this in the form 1gram:n 1gram: n where n n represents the number of water molecules in standard form. (3 marks)

  8. Let's PRACTICE Ratios, Rates and Proportions…step-by-step…

    TabletClass Math:https://tcmathacademy.com/ Math help with rates, ratios and proportions to include practice problems. For more math help to include math le...

  9. Rates and ratios (Pre-Algebra, Ratios and percent)

    Rates and ratios. The ratio is the relationship of two numbers. For example you have 2 flashlights and 5 batteries. To compare the ratio between the flashlights and the batteries we divide the set of flashlights with the set of batteries. The ratio is 2 to 5 or 2:5 or 2/5. All these describe the ratio in different forms of fractions.

  10. Ratio, Proportion and Rates of Change

    Ratio, Proportion and Rates of Change - Short Problems. This is part of our collection of Short Problems. You may also be interested in our longer problems on Ratio, Proportion and Rates of Change. Printable worksheets containing selections of these problems are available here.

  11. Ratios and Rates

    A rate is a unique ratio that compares 2 quantities with different units. For example, if a man covers 3 km in 30 minutes, it is written as 3 km/30 minutes. A unit rate is a rate with a denominator of 1. Let us use the concept of ratios and rates to solve some problems.

  12. How to Solve Rate Problems

    The rate is a ratio of two quantities having different units. Where are they needed? Example 1: ... The exercises below with solutions and explanations are all about solving rate problems. Solve the following rate problems. The distance between two cities on the map is 15 centimeters. The scales on the map is 5 centimeters to 15 kilometers.

  13. Ratios and proportions

    A ratio is a comparison of two quantities. A proportion is an equality of two ratios. To write a ratio: Determine whether the ratio is part to part or part to whole. Calculate the parts and the whole if needed. Plug values into the ratio. Simplify the ratio if needed.

  14. IXL

    17. hr. min. sec. SmartScore. out of 100. IXL's SmartScore is a dynamic measure of progress towards mastery, rather than a percentage grade. It tracks your skill level as you tackle progressively more difficult questions. Consistently answer questions correctly to reach excellence (90), or conquer the Challenge Zone to achieve mastery (100)!

  15. Ratio Worksheets

    These ratio worksheets will generate 16 Ratio and Rate problems per worksheet. These Ratio Worksheets are appropriate for 3rd Grade, 4th Grade, 5th Grade, 6th Grade, and 7th Grade. Ratios and Rates Word Problems Worksheets. These Ratio Worksheets will produce eight ratio and rates word problems for the students to solve.

  16. Ratio: Problem Solving Textbook Exercise

    The Corbettmaths Textbook Exercise on Ratio: Problem Solving. Welcome; Videos and Worksheets; Primary; 5-a-day. 5-a-day GCSE 9-1; 5-a-day Primary; 5-a-day Further Maths ... Ratio: Problem Solving Textbook Exercise. Click here for Questions. Textbook Exercise. Previous: Ratio: Difference Between Textbook Exercise. Next: Reflections Textbook ...

  17. Ratio Practice Questions

    Practice Questions. Previous: Percentages of an Amount (Non Calculator) Practice Questions. Next: Rotations Practice Questions. The Corbettmaths Practice Questions on Ratio.

  18. Word Problems Involving Rates and Ratios

    A step-by-step guide to solving rates and ratios word problems. To solve the word problems involving rates and ratios, follow these steps: Step 1: Find the known ratio and the unknown ratio. Step 2: Write the proportion. Step 3: Use cross-multiply and solve. Step 4: Plug the result into the unknown ratio to check the answers. Word Problems ...

  19. Proportional relationships

    Proportional relationships: graphs. Interpreting graphs of proportional relationships. Worked example: Solving proportions. Writing proportions example. Proportion word problem: cookies. Proportion word problem: hot dogs. Equations for proportional relationships. Writing proportional equations from tables. Writing proportional equations.

  20. Free worksheets for ratio word problems

    Ratio Worksheets. Columns: Rows: (These determine the number of problems) Level: Level 1: write a ratio. Level 2: write a ratio and simplify it. Numbers used (only for levels 1 & 2): Range from to with step. Level 3: word problems.

  21. Can Economic Growth Help Solve US Debt Problem?

    Total tax revenue would be $200 billion. Let's say the economy grows by 5 percent, bringing the new GDP to $1.05 trillion. With the tax rate unchanged at 20 percent, the new tax revenue would be $210 billion—a $10 billion increase without touching the tax rate. A growing economy brings in more tax revenue, which reduces the relative debt ...

  22. Rate problems (practice)

    Rate problems. Video 2 minutes 31 ... Solving unit rate problem. Video 1 minute 56 seconds 1:56. Solving unit price problem. Report a problem. Loading... Learn for free about math, art, computer programming, economics, physics, chemistry, biology, medicine, finance, history, and more. Khan Academy is a nonprofit with the mission of providing a ...

  23. Goldman Now Sees US Debt-Cost Ratio Rising Into Danger Zone

    The average interest rate on the Treasury's outstanding notes and bonds was 3.3% at the end of April, up from 1.4% in January 2022. The Goldman team also forecast the US debt-to-GDP ratio will ...